\(\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{8.9.10}\right).x=\frac{44}{45}\)
\(\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+....+\frac{1}{8.9}-\frac{1}{9.10}\right).x=\frac{44}{45}\)
\(\left(\frac{1}{1.2}-\frac{1}{9.10}\right).x=\frac{44}{45}\)
\(\frac{22}{45}.x=\frac{44}{45}\)
x =2