=> ad< bc
+=> ab+ad < ab+bc => a(b+d)<b(a+c) => \(\frac{a}{b}<\frac{a+c}{b+d};\left(1\right)\)
+ =>ad+cd < bc +cd => d(a+c) < c(b+d) =>\(\frac{a+c}{b+d}<\frac{c}{d};\left(2\right)\)
Từ (1)(2) => dpcm
xóa hết kí ức mà còn nhớ đăng câu hỏi hả??
=> ad< bc
+=> ab+ad < ab+bc => a(b+d)<b(a+c) => \(\frac{a}{b}<\frac{a+c}{b+d};\left(1\right)\)
+ =>ad+cd < bc +cd => d(a+c) < c(b+d) =>\(\frac{a+c}{b+d}<\frac{c}{d};\left(2\right)\)
Từ (1)(2) => dpcm
xóa hết kí ức mà còn nhớ đăng câu hỏi hả??
\(cho\frac{a}{b}=\frac{c}{d}\left(b:d>0\right).CMR\frac{a}{b}=\frac{a+c}{b+d}và\frac{c}{d}=\frac{c-a}{c-d}\)
bài 1: cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\)
a) CMR: (a+2c)(b+d)=(a+c)(b+2d) \(\left(b,d\ne0\right)\)
b) CMR: (a+c)(b-d)=ab-cd
c) CMR: \(\frac{a}{a-b}=\frac{c}{c-d}\left(a,b,c,d>0;a\ne b,c\ne d\right)\)
bài 2: cho \(\frac{a}{b}=\frac{b}{c}=\frac{c}{d}CMR:\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)
1. cho \(\frac{a}{b}=\frac{c}{d};\)(b,c,d khac 0)
cmr: \(\frac{a-b}{a+b}=\frac{c-d}{c+d}\); \(\frac{a\cdot b}{c\cdot d}=\frac{\left(a+b\right)^2}{\left(c+d\right)^2}\)
Nâng cao
a)\(2\left(x-y\right)=5\left(y+z\right)=3\left(x+z\right)\)
\(CMR:\frac{x-y}{4}=\frac{y-z}{5}\)
b)\(Cho\frac{a}{b}=\frac{c}{d}.CMR:\left(a+b+c+d\right)\left(a-b-c+d\right)=\left(a-b+c-d\right)\left(a+b-c-d\right)\)
c)Cho tỉ lệ thức \(\frac{a+b+c}{a+b-c}=\frac{a-b+c}{a-b-c}\) trong đó b khác 0, CMR: c=0
d)Cho tỉ lệ thức \(\frac{a+b}{b+c}=\frac{c+d}{d+a}.CMR:a=c\)hoặc \(a+b+c+d=0\)
Giúp mk vs, mk đang cần gấp, ai nhanh, làm nhiều bài nhất cho 10 tick
1, Cho \(\frac{a}{b}=\frac{c}{d}\)( b,c,d khác 0; c+đ khác 0). CMR:
\(\frac{ab}{cd}=\frac{\left(a+b\right)^2}{\left(c+\text{d}\right)^2}\)
cmr nếu \(\frac{a}{b}=\frac{c}{d}\)
thì: \(\frac{a^2+c^2}{b^2+d^2}=\frac{\left(a+c\right)^2}{\left(b+d\right)^2}\)(b+d khác 0)
\(Cho\frac{a}{b}=\frac{b}{c}=\frac{c}{d}.cmr\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)
Cho: \(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}.CMR:\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)
\(cho\frac{a}{b}=\frac{b}{c}=\frac{c}{d}.CMR:\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)