Question

Cho:

A=\(\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8}\)         ,       B=\(\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)

Chứng minh rằng A>B

Answer 1

A=1/1+5+5^2+5^3+...+5^8+5+5^2+5^3+...+5^9=1/1+5+5^2+5^3+...+5^8+5.

Tương tự B=1/1+3+3^2+...+3^8+3

=>A>B.

k nha.

Answer 2

=> A>B vì A=1+5+5/1

Answer 3

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