Question

cho x,y,z khác 0 và x-y-z=0, tính giá trị của biểu thức B=(1-z/x) (1-x/y) (1+y/z)

Answer 1

x-y-z=0

=> x=y+z

     y=x-z

    -z=y-x

B=(1-z/x)(1-x/y)(1+y/z)

B=((x-z)/x)((y-x)/y)((z+y)/z)

B=(y/x)(-z/y)(x/z)

B=(-z.y.x)/(x.y.z)

B=-1

Answer 2

thank ban nha

Answer 3

B=-1    ^_^

Answer 4

B=-1  ^_^ ^_^ ^_^ ^_^

Answer 5

\(x-y-z=0\)

\(=>x=y-z\)

             \(y=x-z\)

        \(-z=y-x\)

\(B=\left(1-\frac{z}{x}\right).\left(1-\frac{x}{y}\right)\cdot\left(1+\frac{y}{z}\right)\)

\(B=\left[\frac{\left(x-z\right)}{x}\right]\cdot\left[\frac{\left(y-x\right)}{y}\right]\cdot\left[\frac{\left(z+y\right)}{z}\right]\)

\(B=\left(\frac{y}{x}\right)\cdot\left(-\frac{z}{y}\right)\cdot\left(\frac{x}{z}\right)\)

\(B=\frac{\left(-z\cdot y\cdot x\right)}{\left(x\cdot y\cdot z\right)}\)

\(B=-1\)

Answer 6

hello