Mẹo: Làm xuất hiện (xy-1)/xy
\(x^2+y^2=2x^2y^2\Leftrightarrow x^2+y^2-2xy=2xy\left(xy-1\right)\)
\(\Leftrightarrow\frac{xy-1}{xy}=\frac{x^2+y^2-2xy}{2x^2y^2}=\frac{1}{2}\left(\frac{1}{y^2}+\frac{1}{x^2}-\frac{2}{xy}\right)=\frac{1}{2}\left(\frac{1}{x}-\frac{1}{y}\right)^2\)
hm Đề sai ah