Ta có: \(x+y=5\)
\(\Rightarrow\left(x+y\right)^2=5^2\)
\(\Rightarrow x^2+y^2+2xy=25\)
\(\Rightarrow25+2xy=25\) (do \(x^2+y^2=25\))
\(\Rightarrow2xy=0\)
\(\Rightarrow xy=0\)
Ta co': \(x^3+y^3=\left(x+y\right).\left(x^2+y^2-xy\right)\)
\(=5.\left(25-0\right)\)
\(=125\)