\(A=\left(x+y\right)^2-4\left(x+y\right)+1=3^2+4.3+1=22\)
\(A=x^2+2xy+y^2-4x-4y+1\)
\(A=\left(x^2+2xy+y^2\right)-4.\left(x+y\right)+1\)
\(A=\left(x+y\right)^2-4.\left(x+y\right)+1\)
Ta có: \(x+y=3\)
\(\Rightarrow A=3^2-4.3+1\)
\(A=9-12+1\)
\(A=-2\)
Vậy \(A=-2\)tại \(x+y=3\)
Tham khảo nhé~
A = x2 + 2xy + y2 - 4x - 4y + 1
A = (x+y)2 - 4.(x+y) + 1
thay x + y = 3 vao A
co: A = (3)2 - 4.3 + 1
A = 9 - 12 + 1
A = -2