x + y = 2 <=> x = 2 - y (1)
x2 + y2 = 10 <=> (x + y).(x - y) = 10 <=> 2(x - y) = 10 <=> x - y = 5 <=> x = 5 + y (2)
Từ (1)(2) suy ra 2 - y = 5 + y <=> 2y = - 3 <=> y = -1,5 => x = 3,5
x3 + y3 = 3,53 + (-1,5)3 = ...
x2 + y2 = 10 <=> ( x + y )2 - 2xy = 10 <=> 4 - 2xy = 10 <=> -2xy = 6 <=> xy = -3
Khi đo : x3 + y3 = ( x + y )3 - 3xy( x + y ) = 8 + 12 = 20