Ta có : \(\frac{2x+y}{x+y}=\frac{2016}{2015}\)
\(\Rightarrow\frac{x+y+x}{x+y}=\frac{2015+1}{2015}\)
\(\Rightarrow1+\frac{x}{x+y}=1+\frac{1}{2015}\)
\(\Rightarrow\frac{x}{x+y}=\frac{1}{2015}\)
\(\Rightarrow2015x=x+y\)
\(\Rightarrow y=2014x\)
Vậy \(y=2014x\)