Ta có:
\(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^o\)(Tổng các góc trong một tứ giác)
\(\Rightarrow\widehat{D}=360^o-\left(\widehat{A}+\widehat{B}+\widehat{C}\right)\)
\(=360^o-\left(47^o+98^o+125^o\right)=90^o\)
Vậy \(\widehat{D}=90^o\)
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