\(\frac{a}{b}\)= \(\frac{c}{d}\)=> \(\frac{a}{c}\)= \(\frac{b}{d}\)= \(\frac{4a}{4c}\)= \(\frac{6b}{6d}\)= \(\frac{4a+6b}{4c+6d}\)
\(\frac{a}{c}\)= \(\frac{b}{d}\)= \(\frac{5a}{5c}\)= \(\frac{7b}{7d}\)= \(\frac{5a-7b}{5c-7d}\)
=> \(\frac{4a+6b}{4c+6d}\)= \(\frac{5a-7b}{5c-7d}\)
=> \(\frac{4a+6b}{5a-7b}\)= \(\frac{4c+6d}{5c-7d}\)