Gọi \(\frac{a}{b}=\frac{c}{d}=k\)
\(\Rightarrow a=kb;c=kd\)
Ta xét :
\(\frac{a-b}{b}=\frac{kb-b}{b}=\frac{b\left(k-1\right)}{b}=k-1\)
\(\frac{c-d}{d}=\frac{kd-d}{d}=\frac{d\left(k-1\right)}{d}=k-1\)
Ta thấy \(k-1=k-1\)
\(\Rightarrow\frac{a-b}{b}=\frac{c-d}{d}\)
\(\RightarrowĐPCM\)
Rất dễ:
Ta có: \(\frac{c}{d}=\frac{a}{b}\Rightarrow\frac{a}{b}-1=\frac{c}{d}-1\)
\(\Rightarrow\frac{a-b}{c}=\frac{c-d}{d}\)
ĐPCM
Ta có
\(\frac{a}{b}=\frac{a}{d}\Leftrightarrow\frac{a}{b}-1=\frac{c}{d}-1\Leftrightarrow\frac{a}{b}-\frac{b}{b}=\frac{d}{c}-\frac{d}{d}\Leftrightarrow\)\(\frac{a-b}{b}=\frac{c-d}{d}\)
Ta có :\(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{b}-1=\frac{c}{d}-1\Rightarrow\frac{a-b}{b}=\frac{c-d}{d}\)
\(\RightarrowĐPCM\)