Ta có
tan 2 = \(\dfrac{sin2}{cos2}\)
ma tan 2 = \(\dfrac{1}{3}\)
=> sin 2 = 1; cos 2 = 3
\(\dfrac{cos2-sin2}{cos2-sin2}=\dfrac{3-1}{3-1}=\dfrac{2}{2}=1\)
Đúng 0
Bình luận (0)