a) Xét \(\Delta AEB\)và \(\Delta AFC\)có :
\(\widehat{BAC}\)chung
\(\widehat{AEB}=\widehat{AFC}\left(=90^0\right)\)
\(\Rightarrow\Delta AEB~\Delta AFC\left(g-g\right)\)
\(\Rightarrow\frac{AE}{AF}=\frac{AB}{AC}\)
\(\Rightarrow AE\cdot AC=AF\cdot AB\)( đpcm )
b) Xét \(\Delta AFE\)và \(\Delta ACB\)có :
\(\widehat{BAC}\)chung
\(\frac{AE}{AF}=\frac{AB}{AC}\)( câu a )
\(\Rightarrow\Delta AFE~\Delta ACB\left(c-g-c\right)\)( đpcm )
c) đang nghĩ .-.