Xét \(\Delta\)ABC có DE //BC
=> \(\frac{AD}{AB}=\frac{AE}{AC}\)( ta lét)
=> \(\frac{AC}{AB}=\frac{AE}{AD}=\frac{AC-EC}{AD}=\frac{AC-AD}{AD}\)( vì AD = CE)
=> \(\frac{AC}{AB}=\frac{AC}{AD}-1\)
Khi đó: \(\frac{10}{6}=\frac{10}{AD}-1\)
<=> \(\frac{10}{AD}=\frac{16}{6}\)
<=> AD= 10.6 : 16 = 3,75