Question

Cho tam giác ABC. CMR G là trọng tâm tam giác ABC ta có:

\(\overrightarrow{GA}\cdot\overrightarrow{GB}+\overrightarrow{GB}\cdot\overrightarrow{GC}+\overrightarrow{GC}\cdot\overrightarrow{GA}=\frac{1}{6}\left(AB^2+BC^2+CA^2\right)\)

Answer 1

\(\overrightarrow{GA}+\overrightarrow{GB}+\overrightarrow{GC}=\overrightarrow{0}\Rightarrow\left(\overrightarrow{GA}+\overrightarrow{GB}+\overrightarrow{GC}\right)^2=0\)

\(\Rightarrow-2\left(\overrightarrow{GA}.\overrightarrow{GB}+\overrightarrow{GB}.\overrightarrow{GC}+\overrightarrow{GC}.\overrightarrow{GA}\right)=GA^2+GB^2+GC^2\)

\(\Rightarrow\overrightarrow{GA}.\overrightarrow{GB}+\overrightarrow{GB}.\overrightarrow{GC}+\overrightarrow{GC}.\overrightarrow{GA}=-\frac{1}{2}\left(\frac{2}{3}m_a^2+\frac{2}{3}m_b^2+\frac{2}{3}m_c^2\right)\)

\(=-\frac{1}{6}\left(AB^2+BC^2+CA^2\right)\)

Hình như đề bài sai dấu?