Các câu hỏi tương tự
A= \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
B= \(\frac{\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}}{\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}}\)
cho A=\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}\)
chung minh rang
a) A =\(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{99}+\frac{1}{100}\)
b) \(\frac{25}{75}+\frac{25}{100}< A< \frac{25}{51}+\frac{25}{75}\)
chứng minh: \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}=\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\)
Cho A = \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}\)
CMR:
1, A = \(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{99}+\frac{1}{100}\)
2, \(\frac{25}{75}+\frac{25}{100}< A< \frac{25}{51}+\frac{25}{75}\)
a)Afrac{1}{1.2}+frac{1}{2.3}+frac{1}{3.4}+...+frac{1}{99.100} 1b)Bfrac{1}{3}+left(frac{1}{3}right)^2+left(frac{1}{3}right)^3+...+left(frac{1}{3}right)^{100} frac{1}{2}c)frac{1}{1.2}+frac{1}{3.4}+frac{1}{5.6}+...+frac{1}{49.50}frac{1}{26}+frac{1}{27}+...+frac{1}{50}d)Afrac{1}{1.2}+frac{1}{3.4}+...+frac{1}{99.100}.CMRfrac{7}{12} A frac{5}{6}AI ĐÚNG MINK left(TICKright)CHO (làm đc trên 2 câu)
Đọc tiếp
a)A=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}< 1\)
b)B=\(\frac{1}{3}+\left(\frac{1}{3}\right)^2+\left(\frac{1}{3}\right)^3+...+\left(\frac{1}{3}\right)^{100}< \frac{1}{2}\)
c)\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{49.50}=\frac{1}{26}+\frac{1}{27}+...+\frac{1}{50}\)
d)A=\(\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{99.100}.CMR\frac{7}{12}< A< \frac{5}{6}\)
AI ĐÚNG MINK \(\left(TICK\right)\)CHO (làm đc trên 2 câu)
cho A=\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}vàB=\frac{2013}{51}+\frac{2013}{52}+\frac{2013}{53}+...+\frac{2013}{100}\)
Chứng Minh \(\frac{B}{A}\)là số nguyên
cho\(A=\frac{1}{1.2}+\frac{1}{3.4}+.........+\frac{1}{99.100}CMR\frac{7}{12}< A< \frac{5}{6}\)
Cho A=\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.......+\frac{1}{99.100}\)
và B=\(\frac{2013}{51}+\frac{2013}{52}+\frac{2013}{53}+.....+\frac{2013}{100}\)
Chúng minh rằng:\(\frac{B}{A}\)là một số nguyên
\(y=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{4.5}+.......+\frac{1}{99.100}\)
\(B=\frac{1}{50}+\frac{1}{51}+\frac{1}{52}+.......+\frac{1}{100}\)
TÍNH GIÁ TRỊ CỦA : Y - B = ?