Question

Cho S=2^2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10
Ai nhanh mình tick nhé

Answer 1

Bạn ơi chỗ \(2^2+2^2\) thì phải là \(2^1+2^2\) chứ

Answer 2

Sửa lại thì thành

          \(S=2^1+2^2+2^3+...+2^{10}\)

        \(2S=2^2+2^3+2^4+...+2^{11}\)

\(2S-S=\left(2^2+2^3+2^4+....+2^{11}\right)-\left(2^1+2^2+2^3+...+2^{10}\right)\)

          \(S=2^{11}-2\)

Answer 3

S=2^2+2^2+2^3+2^4+...+2^10

S=2.2^2+2^3+2^4+...+2^10

S=2^3+2^3+2^4+...+2^10

S=2.2^3+2^4+...+2^10

S=2^4+2^4+...+2^10

S=2.2^4+...+2^10

S=2^5+2^5...+2^10

...

S=2^10+2^10

S=2.2^10

S=2^11

Answer 4

cách 2:

S=2^2+2^2+2^3+...+2^10

2S=2^3+2^3+2^4+...+2^11

2S-S=(2^3+2^3+2^4+...+2^11)-(2^2+2^2+2^3+...+2^10)

S=2^11+(2^10-2^10)+(2^9-2^9)+...+(2^3-2^3)+(2^3-2^2-2^2)

S=2^11+0+0+...+0+(2^3-2.2^2)

S=2^11+(2^3-2^3)

S=2^11+0

S=2^11