Các câu hỏi tương tự
Cho S = \(-\frac{4}{1}.\frac{4}{5}-\frac{4}{5}.\frac{4}{9}-\frac{4}{9}.\frac{4}{13}-...-\frac{4}{2013}.\frac{4}{2017}\) Vậy, 2017S bằng bao nhiêu ?
Cho S = \(-\frac{4}{1}.\frac{4}{5}-\frac{4}{5}.\frac{4}{9}-.......-\frac{4}{2013}.\frac{4}{2017}\)
Hỏi 2017S = ........
MN trình bày giùm mình nha Arigato ( cúi đầu)
Tính \(S=-\frac{4}{1}.\frac{4}{5}-\frac{4}{5}.\frac{4}{9}-\frac{4}{9}-\frac{4}{13}-...-\frac{4}{2013}.\frac{4}{2017}\)
Cho S = -\(\frac{4}{1}\). \(\frac{4}{5}\)-\(\frac{4}{5}\). \(\frac{4}{9}\)-\(\frac{4}{9}\).\(\frac{4}{13}\)-....- \(\frac{4}{2013}\).\(\frac{4}{2017}\)
Tính 2017S
Tính S = \(\frac{-4}{1}\). \(\frac{4}{5}\)- \(\frac{4}{5}\). \(\frac{4}{9}\)- \(\frac{4}{9}\). \(\frac{4}{13}\) -...- \(\frac{4}{2013}\). \(\frac{4}{2017}\)
\(\left(-1\frac{1}{6}\right)\left(\frac{1-\frac{3}{5}+\frac{3}{11}-\frac{3}{13}}{\frac{1}{3}-\frac{1}{5}+\frac{1}{11}-\frac{1}{13}}\right):\left(\frac{4-\frac{4}{17}+\frac{4}{19}-\frac{4}{2013}}{5-\frac{5}{17}+\frac{5}{19}-\frac{5}{2013}}\right)\)
tính
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
a)\(\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{5}\right)+\left(\frac{-9}{11}+\frac{4}{5}\right).\frac{5}{7}\) b)\(2\frac{2}{5}.\frac{5}{9}+1\frac{4}{9}.\frac{12}{5}-1,8.\frac{10}{3}\)c)\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{4}{13}-\frac{2}{13}.\frac{-7}{25}\)
1. Tính:
a. \(75\%-1\frac{1}{2}.\frac{4}{3}+1,5:\frac{-9}{4}-\left(-\frac{1}{2}\right)^2\)
b. \(\frac{-4}{9}.\frac{6}{13}+7\frac{4}{9}-\frac{4}{9}:\frac{13}{7}-5\frac{4}{9}-2\)
2. Tìm x, biết:
a. \(x\in Z,-1\le\frac{x}{5}< 0\)
*làm nhanh nha, mk cần gấp lắm