Pt có nghiệm=>\(\Delta^'\ge0\)
=>9-2(m-2)≥0
=>13-2m≥0
=>m≤\(\frac{13}{2}\)
Theo Viet ta có:\(\hept{\begin{cases}x_1+x_2=3\\x_1x_2=\frac{m-2}{2}\end{cases}}\)
Khi đó:\(A=x_1^2+x_2^2=\left(x_1+x_2\right)^2-2x_1x_2=11-m\)
=>\(A\ge11-\frac{13}{2}=\frac{9}{2}\)
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