Các câu hỏi tương tự
AI BIẾT LÀM HỘ NHA ! TỚ TICK CHO
1, A= \(\frac{x+2}{x\sqrt{x-1}}+\frac{\sqrt{x+1}}{x+\sqrt{x+1}}-\frac{1}{\sqrt{x-1}}\)
2, chứng minh biểu thức sau có giá trị ko phụ thuộc vào x
A= \(\sqrt{x}+\frac{3\sqrt{2-\sqrt{3}}.6\sqrt{7+4\sqrt{3}}-x}{4\sqrt{9-4\sqrt{5}}.\sqrt{2}+\sqrt{5}+\sqrt{x}}\)
Giải bất phương trình :
\(\frac{x-1}{2}+\frac{x-2}{3}+\frac{x-3}{4}>\frac{x-4}{5}+\frac{x-5}{6}\)
Mình rút gọn như thế này đúng không nhỉ?Pleft(2-frac{sqrt{x}-1}{2sqrt{x}-3}right):left(frac{6sqrt{x}+1}{2x-sqrt{x}-3}+frac{sqrt{x}}{sqrt{x}+1}right)Pleft[frac{2left(2sqrt{x}-3right)}{2sqrt{x}-3}-frac{sqrt{x}-1}{2sqrt{x}-3}right]:left[frac{6sqrt{x}+1}{left(sqrt{x}+1right)left(2sqrt{x}-3right)}+frac{sqrt{x}left(2sqrt{x}-3right)}{left(sqrt{x}+1right)left(2sqrt{x}-3right)}right]Pleft(frac{4sqrt{x}-6}{2sqrt{x}-3}-frac{sqrt{x}-1}{2sqrt{x}-3}right):left(frac{6sqrt{x}+1}{left(sqrt{x}+1right)left(2sqrt{x...
Đọc tiếp
Mình rút gọn như thế này đúng không nhỉ?
\(P=\left(2-\frac{\sqrt{x}-1}{2\sqrt{x}-3}\right):\left(\frac{6\sqrt{x}+1}{2x-\sqrt{x}-3}+\frac{\sqrt{x}}{\sqrt{x}+1}\right)\)
\(P=\left[\frac{2\left(2\sqrt{x}-3\right)}{2\sqrt{x}-3}-\frac{\sqrt{x}-1}{2\sqrt{x}-3}\right]:\left[\frac{6\sqrt{x}+1}{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}+\frac{\sqrt{x}\left(2\sqrt{x}-3\right)}{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}\right]\)
\(P=\left(\frac{4\sqrt{x}-6}{2\sqrt{x}-3}-\frac{\sqrt{x}-1}{2\sqrt{x}-3}\right):\left(\frac{6\sqrt{x}+1}{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}+\frac{2x-3\sqrt{x}}{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}\right)\)
\(P=\left(\frac{4\sqrt{x}-6-\sqrt{x}+1}{2\sqrt{x}-3}\right):\left(\frac{6\sqrt{x}+1+2x-3\sqrt{x}}{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}\right)\)
\(P=\frac{3\sqrt{x}-5}{2\sqrt{x}-3}:\frac{2x+3\sqrt{x}+1}{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}\)
\(P=\frac{3\sqrt{x}-5}{2\sqrt{x}-3}.\frac{\left(\sqrt{x}+1\right)\left(2\sqrt{x}-3\right)}{2x+3\sqrt{x}+1}\)
\(P=\left(3\sqrt{x}-5\right).\frac{\left(\sqrt{x}+1\right)}{2x+3\sqrt{x}+1}\)
\(P=\frac{3x+3\sqrt{x}-5\sqrt{x}-5}{2x+3\sqrt{x}+1}\)
\(P=\frac{3x-5\sqrt{x}-5}{2x+1}\)
Giúp mk vs ạ!
1)Cho M(x)=\(1-\frac{1}{2^2}+\frac{2}{3^2}-\frac{3}{4^2}+......+\left(-1\right)^{x+1}\frac{x-1}{x^2}\)
Tính M(3) M(6) M(20) M(25) M(30)
2)Tính:
A=\(\left(1-\frac{2}{1.2.3}\right)^4+\left(3-\frac{5}{2.3.4}\right)^4+\left(5-\frac{10}{3.4.5}\right)^4+......+\left(59-\frac{901}{30.31.32}\right)^4\)
\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-5}+2=0\)
\(2x-x^2+\sqrt{6x^2-12x+7}=0\)
\(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6\)
\(\frac{1}{2}\sqrt{x-1}-\frac{3}{2}\sqrt{9x-9}+24\sqrt{\frac{x-1}{64}}=-17\)
giúp dùm đi mấy pạn
let x,y,z>0 such that xyz=1. show that \(\frac{x^3+1}{\sqrt{x^4+y+z}}+\frac{y^3+1}{\sqrt{y^4+z+x}}+\frac{z^3+1}{\sqrt{x^4+x+y}}\ge2\sqrt{xy+yz+zx}\)
giải các phương trình sau:
a, \(\sqrt{x^2-1}=x-2\)
b, \(\frac{5}{\sqrt{2x^2+1}}=1\)
c, \(\sqrt{x^2}+\sqrt{x^2-2x+1}=2\)
d, \(\frac{x^2}{9}+\frac{16}{x^2}=\frac{10}{3}\left(\frac{x}{3}-\frac{4}{x}\right)\)
chứng minh \(\frac{1}{x}+\frac{1}{y}\le2\) biết \(x^3+y^3+3\left(x^2+y^2\right)+4\left(x+y\right)+4=0;xy>0\)
Cho \(P=\frac{10\sqrt{x}}{x+3\sqrt{x}-4}-\frac{2\sqrt{x}-3}{\sqrt{x}+4}+\frac{\sqrt{x}+1}{1-\sqrt{x}}\)
a. Rút gọn P
b. C/m: P> -3
c. Tìm GTLN của P