Question

Cho P= \(\frac{\sqrt{x}}{\sqrt{x}+3}+\frac{2\sqrt{x}}{\sqrt{x}-3}-\frac{3x+9}{x-9}\)

a) Rút gọn bt P

b) Tìm x để P=\(\frac{1}{3}\)

*** Mong mọi người sẽ giúp đỡ em***

 

Answer 1

\(P=\frac{\sqrt{x}\left(\sqrt{x}-3\right)+2\sqrt{x}\left(\sqrt{x}+3\right)-3x-9}{x-9}\)             dk \(x\ge0;x\ne9\)

\(=\frac{x-3\sqrt{x}+2x+6\sqrt{x}-3x-9}{x-9}\)

\(=\frac{3\sqrt{x}-9}{x-9}=\frac{3\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\frac{3}{\sqrt{x}+3}\)

b)

\(P=\frac{1}{3}\Leftrightarrow\frac{3}{\sqrt{x}+3}=\frac{1}{3}\Leftrightarrow\sqrt{x}+3=9\Leftrightarrow\sqrt{x}=6\Leftrightarrow x=36\)

vay ......................................

nếu có sai bn thông cảm nha