tim n thuoc N sao cho
n.(n+6) la so nguyen to
n^2+10.n la so nguyen to
tim n thuoc N de 3n + 60 la so nguyen to
tim x thuoc N biet 97.x la so nguyen to ( . la dau nhan)
tim n thuoc Z de so p=10/n^2+4 la so nguyen to chan
a, tim so nguyen to P+10; p+20 cung la so nguyen to
b, tim UCLN(3n+2;4-1);(a thuoc N)
1) Biet rang 996 va 632 khi chia cho n deu du 16 . Tim n.
2) Chung minh rang 7n + 10 va 5n + 7 la hai so nguyen to cung nhau ( n thuoc N )
3) Biet rang 7a + 2b chia het cho 13 (a,b thuoc N) . Chung minh rang 10a + b cung chia het cho 13
Biet rang 3n cong 1 va 5n cong 4 (n thuoc N ) la 2 so khong nguyen to cung nhau . Tim UCLN cua 2 so tren
tim cac so nguyen duong n sao cho n^2/60-n la 1 so nguyen to
Bai1 a,cho n thuoc N. Chung minh rang 6n+5 va 4n+3 la 2 so nguyen to cung nhau
b, tim so nguyen x sao cho x+2016 la so nguyen duong nho nhat