Question

cho mk hoi voi:

tim so nguyen n sao cho

2n-1 chia het cho n+ 1

Answer 1

Do n+1\(⋮\)n+1 => 2n+2\(⋮\)n+1.

Theo đề bài => 2n+2-(2n-1)\(⋮\)n+1 hay 3\(⋮\)n+1

=> n+1\(\in\){-3;-1;1;3}

Vậy n\(\in\){-4;-2;0;3}