hay so sanh m voi 1
M=\(\frac{1}{2!}+\frac{2}{3!}++......+\frac{9}{10!}\)
\(M=\frac{1}{2}-\frac{1}{2^4}+\frac{1}{2^7}-\frac{1}{2^{10}}+......+\frac{1}{2^{\text{49}}}-\frac{1}{2^{52}}\)
so sanh m voi 9/4
nhờ giải đầy đủ nha ai làm đc mình tick cho\
A=\(\frac{455}{1}+\frac{454}{2}+....+\frac{2}{454}+\frac{1}{455}\)
hay so sanh A voi 2018
Cho A=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right).....\left(\frac{1}{100^2}-1\right)\)
So sanh A voi \(\frac{1}{2}\)
C = \(\frac{1+\frac{1}{3}+\frac{1}{3^2}+....+\frac{1}{3^{100}}}{1+\frac{1}{3}+......+\frac{1}{3^{101}}}\)
D = \(\frac{1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{101}}}{1+\frac{1}{3}+........+\frac{1}{3^{102}}}\)
ai lam ho minh voi so sanh nha
Cho \(A=\left(\frac{1}{^{2^2}}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)......\left(\frac{1}{2013^2}-1\right).\left(\frac{1}{2014^2}-1\right)va\)\(B=-\frac{1}{2}.\)Hay so sanh A va B
Cho A= \(\frac{1}{5^2}+\frac{2}{5^3}+\frac{3}{5^4}+..............+\frac{11}{5^{12}}\)so sanh A voi \(\frac{1}{16}\)
cho A=1+\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{4026},B=1+\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+...+\frac{1}{4025}\)so sanh \(\frac{A}{B}\)voi\(1\frac{2013}{2014}\)
So sanh
\(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{90}+\frac{1}{100}.\)va 100
cac ban giai chi tiet giup mk voi