Question

cho m=2+2^2+2^3+2^4+............+2^20

chung to m chia het cho 5. giai thich va neu cach lam

Answer 1

\(M=2+2^2+2^3+2^4+..........+2^{20}\)

\(\Rightarrow M=\left(2+2^2+2^3+2^4\right)+........+\left(2^{17}+2^{18}+2^{19}+2^{20}\right)\)

\(\Rightarrow M=2\times\left(1+2+2^2+2^3\right)+...+2^{17}\times\left(1+2+2^2+2^3\right)\)

\(\Rightarrow M=2\times15+...+2^{17}\times15\)

\(\Rightarrow M=15\times\left(2+.....+2^{17}\right)=3\times5\left(2+...+2^{17}\right)\text{ }\text{ }⋮\text{ }5\)

\(\Rightarrow M\text{ }⋮\text{ }5\)

Answer 2

Mình Ko Ghi Lịa Đề Nhé!

M=2*(1+2+2^2+2^3)+...+2^17-(1+2+2^2+^3)

M=2*15+...+2^17*15

M=15*(2+...+2^17)chia het cho 

Vì 15 chia hết cho 5

Vậy M chia hết cho 5

Answer 3

neu dung thi k cho cai tren nhe!

thanks

bye