Question

Cho M = \(\frac{3}{\sqrt{x}-2}\)+ \(\frac{2}{\sqrt{x}+2}\)+ \(\frac{8}{x-4}\)

Answer 1

Rút gọn hả bn

ĐKXĐ: \(x\ne4\)

\(M=\frac{3}{\sqrt{x}-2}+\frac{2}{\sqrt{x}+2}+\frac{8}{x-4}\)

\(M=\frac{3.\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right).\left(\sqrt{x}+2\right)}+\frac{2.\left(\sqrt{x}-2\right)}{\left(\sqrt{x}+2\right).\left(\sqrt{x}-2\right)}+\frac{8}{\left(\sqrt{x}-2\right).\left(\sqrt{x}+2\right)}\)

\(M=\frac{3\sqrt{x}+6+2\sqrt{x}-4+8}{\left(\sqrt{x}-2\right).\left(\sqrt{x}+2\right)}\)

\(M=\frac{5\sqrt{x}+10}{\left(\sqrt{x}-2\right).\left(\sqrt{x}+2\right)}=\frac{5.\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right).\left(\sqrt{x}+2\right)}=\frac{5}{\sqrt{x}-2}\)