pt <=> \(\left(\sqrt{x^2+2013}+x\right)\) . \(\left(\sqrt{x^2+2013}-x\right)\). \(\left(\sqrt{y^2+2013}+y\right)\)= 2013 . \(\left(\sqrt{x^2+2013}-x\right)\)
<=> 2013 . \(\left(\sqrt{y^2+2013}+y\right)\)= 2013 . \(\left(\sqrt{x^2+2013}-x\right)\)
<=> \(\sqrt{y^2+2013}+y\)= \(\sqrt{x^2+2013}-x\)
Tương tự : \(\sqrt{x^2+2013}+x\)= \(\sqrt{y^2+2013}-y\)
=> x=-y
=> x+y = 0
Tk mk nha