u ở mẫu là cái gì vậy ?
Chàng Trai 2_k_7
Các câu hỏi tương tự
Cho :
\(\left(2x_1-3y_1\right)^{2016}+\left(2x_2-3y_2\right)^{2016}+...+\left(2x_{2015}-2y_{2015}\right)^{2016}\le0\)
Tính \(A=\frac{x_1+x_2+x_3+...+x_{2015}}{y_1+y_2+y_3+...+y_{2015}}\)
Cho:
( 2017x1 - 2016y2 )2 + ( 2017x2 - 2016y2 )2 + ... + ( 2017x2016 - 2016x2016)2 \(\le\)0
Chứng minh \(\frac{x_1+x_2+...+x_{2016}}{y_1+y_2+...+y_{2016}}=\frac{2016}{2017}\)
Cho \(A=\left(x_1+2y_1\right)^2+\left(2x_2+4y_2\right)^2+.......+\left(100x_{100}+200y_{100}\right)\le0\)
Hỏi \(B=\frac{x_1+x_2+......+x_{100}}{y_1+y_2+......+y_{100}}=?\)
Cho \(\left(x_1a-y_1b\right)^{2n}+\left(x_2a-y_2b\right)+\left(x_3a-y_3b\right)+...+\left(x_ma-y_mb\right)\le0\left(m,n\inℕ^∗\right)\)
Chứng minh \(\frac{x_1+x_2+x_3+...+x_m}{y_1+y_2+y_3+...+y_m}=\frac{b}{a}\)
Cho:
\(\frac{x_1-1}{2017}=\frac{x_2-2}{2016}=\frac{x_3-3}{2015}=...=\frac{x_{2017}-2017}{1}vàx_1+x_2+...+x_{2017=2017\cdot2018.}Tìmx_1,x_2,x_{3,...,x_{2017}?}\)
CHO CÁC SỐ DƯƠNG a,b,c khác d và \(\frac{a}{b}=\frac{c}{d}\)
CMR. \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}=\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-b^{2017}\right)^{2016}}\)
Cho (2x1-3y1)2016+(2x2-3y2)2016+............+(2x2015-3y2015)2016 nhỏ hơn hoặc bằng. Tính A=\(\frac{x_1+x_2+.......+x_{2015}}{y_1+y_2+.......+y_{2015}}\)
A frac{frac{3}{4}-frac{3}{11}+frac{3}{13}}{frac{5}{4}-frac{5}{11}+frac{5}{13}}+frac{frac{1}{2}-frac{1}{3}+frac{1}{4}}{frac{5}{4}-frac{5}{6}+frac{5}{8}}B frac{2^{12}.3^5-4^6.9^2}{left(2^2.3right)^6+8^4.3^5}-frac{5^{10}.7^3-25^5.49}{left(125.7right)^3+5^9.14^3}C frac{left(a^{2016}+b^{2016}right)^{2017}}{left(c^{2016}+d^{2016}right)^{2017}} frac{left(a^{2017}-b^{2017}right)^{2016}}{left(c^{2017}-d^{2017}right)^{2016}}
Đọc tiếp
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
C = \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}\)= \(\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-d^{2017}\right)^{2016}}\)
chứng tỏ \(\frac{10^{2016}+2^3}{9}\) là số tự nhiên
So sánh A=\(\left(1+\frac{1}{2016}\right)\left(1+\frac{1}{2016^2}\right)\left(1+\frac{1}{2016^3}\right)...\left(1+\frac{1}{2016^{2017}}\right)\)
\(B=\frac{2016^2-1}{2015^2-1}\)