Các câu hỏi tương tự
Cho K = \(\frac{4}{3}\)+ \(\frac{13}{3^2}+\frac{22}{3^2}+....\frac{904}{3^{101}}\). Chứng minh : K < \(\frac{17}{4}\)
1. cho A = \(\frac{4}{3}+\frac{7}{3^2}+\frac{10}{3^3}+...+\frac{301}{3^{100}}\)chứng minh: A< \(\frac{11}{4}\)
2. cho B = \(\frac{11}{3}+\frac{17}{3^2}+\frac{23}{3^3}+...+\frac{605}{3^{100}}\)chứng minh: B<7
3. cho C = \(\frac{4}{3}+\frac{13}{3^2}+\frac{22}{3^3}+...+\frac{904}{3^{101}}\)chứng minh: C<\(\frac{17}{4}\)
26 tháng 7 2015 lúc 13:03
CMR: \(A=\frac{1}{3}+\frac{2}{3^2}+\frac{3}{3^3}+\frac{4}{3^4}+...+\frac{101}{3^{101}}+\frac{102}{3^{102}}<\frac{3}{4}\)
\(\left(\frac{-3}{8}+\frac{5}{9}:\frac{-11}{37}\right).\left(\frac{33}{19}-\frac{7}{22}.\frac{43}{17}\right).\left(2-\frac{7}{13}.\frac{7}{26}\right)\)
Giúp mk đi , mk k hết cho mn
CMR:
a)\(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\) <1
b)\(\frac{1}{3}+\frac{2}{3^2}+\frac{3}{3^3}+\frac{4}{4^4}+....+\frac{101}{3^{101}}\),<3/4
nhanh nhé
\(A=1-\frac{3}{4}+\left(\frac{3}{4}\right)^2-\left(\frac{3}{4}\right)^3+\left(\frac{3}{4}\right)^4-...-\left(\frac{3}{4}\right)^{2009}+\left(\frac{3}{4}\right)^{2010}\)
CMR: A k thuộc Z
16 tháng 2 2020 lúc 10:02
Tính : \(K=\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}\right).3^5+\left(\frac{1}{3^5}+\frac{1}{3^6}+\frac{1}{3^7}+\frac{1}{3^8}.3^9\right)+...+\left(\frac{1}{3^{97}}+\frac{1}{3^{98}}+\frac{1}{3^{99}}+\frac{1}{3^{100}}\right).3^{101}\)
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
a. M=\(\frac{75-\frac{6}{13}+\frac{3}{17}-\frac{3}{19}}{275-\frac{22}{13}+\frac{11}{17}-\frac{11}{19}}\)
b. B=\(\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{7}-\frac{2}{13}}.\)\(\frac{\frac{1}{3}-0,25+0,2}{1\frac{1}{6}-0,875+0,7}\)