Xét tg ABC và tg MCD có đường cao từ C->AB = đường cao từ M->CD nên
\(\frac{S_{ABC}}{S_{MCD}}=\frac{AB}{CD}=\frac{2}{3}\Rightarrow S_{MCD}=\frac{3xS_{ABC}}{2}=\frac{3x48}{2}=72cm^2\)
Bạn tham khảo link này nhé
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