Cô hướng dẫn nhé.
Ta thấy \(\Delta DAA'\sim\Delta ECC'\sim\Delta EBB'\left(g-g\right)\)
\(\Rightarrow\frac{CC'}{AA'}=\frac{EC}{AD};\frac{BB'}{AA'}=\frac{EB}{DA}\)
Như vậy \(\frac{CC'}{AA'}+\frac{BB'}{AA'}=\frac{EC}{DA}+\frac{EB}{DA}=\frac{BC}{DA}=1\Rightarrow CC'+BB'=AA'.\)