b,\(f\left(a\right)=2a-24\)
\(-f\left(-a\right)=-\left(2\left(-a\right)-24\right)=2a+24\)
Cộng cả 2 vế của BĐT \(-24< 24\), với \(2a\), ta có :
\(2a-24< 2a+24\)
Vậy \(f\left(a\right)< -f\left(-a\right)\)
a) f(1)= 2x1 - 8x3= 2-24=-22
f(-1)= -26; f(0,5)= -23; f(-0,5)= -25
b) f(a) > f(-a)
y = f(x) = 2x - 24
a) f(1) = 2.1 -24 = -22
f(-1) = 2. (-1) - 24 = -26
f(0,5) = 2. 0,5 - 24 =-23
f(-0,5) = 2. (-0,5) - 24 =-25
b) f(a) = 2a - 24
-f(-a) = -( -2a - 24)=2a + 24
nên f(a) <- f(-a)
a,\(y=f\left(x\right)=2x-8.3=2x-24\)
\(f\left(1\right)=2.1-24=-22\)
\(f\left(-1\right)=2\left(-1\right)-24=-2-24=-26\)
\(f\left(0,5\right)=2.0,5-24=1-24=-23\)
\(f\left(-0,5\right)=2.\left(-0,5\right)-24=-1-24=-25\)