X:y=4:5<=>x/4=y/5
Đặt x/4=y/5=k=>x=4k;y=5k
=>xy=(4k).(5k)=20k^2=5=>k^2=1/4=(+1/2)^2
Mà x,y<0
=>k=-1/2
=>x=-2;y=-5/2
\(x:y=4:5\Rightarrow\frac{x}{4}=\frac{y}{5}\)
Đặt x = 4k , y = 5k
Ta có: 4k.5k = 5 => 20k2=5 => k2= \(\frac{1}{4}\)=> k = \(\frac{1}{2}\)
=> x = 4.\(\frac{1}{2}\) = 2
y = 5.\(\frac{1}{2}\) = 2,5