Question

Cho hai góc kề nhau \(\widehat{AOB}\) và \(\widehat{BOC}\) với \(\widehat{AOC}\) = 80^o. Biết \(\widehat{AOB}\) = \(\dfrac{1}{5}\) \(\widehat{AOC}\). Tính số đo các góc \(\widehat{AOB}\) và \(\widehat{BOC}\). 

dễ hiểu ạ ko chép mạng ^^

Answer 1

Ta có: \(\widehat{AOB}=\dfrac{1}{5}\widehat{AOC}\)

Mà \(\widehat{AOC}=80^o(GT)\)
\(\Rightarrow \widehat{AOB}=80^o.\dfrac{1}{5}=16^o\)

Lại có: \(\widehat{BOC}=\widehat{AOC}+\widehat{AOB}\) 
                 \(\rightarrow\widehat{BOC}=80^o+16^o\)
                 \(\rightarrow\widehat{BOC}=96^o\)