Question

Cho \(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=0\)

        \(\frac{a}{x}+\frac{b}{y}+\frac{c}{x}=2\)Tính giá trị biểu thức

\(D=\left(\frac{a}{x}\right)^2+\left(\frac{b}{y^2}\right)^2+\left(\frac{c}{z}\right)^2\)

Answer 1

Vì \(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=0\)

\(\Rightarrow\frac{bcx+acy+abz}{abc}=0\)

\(\Rightarrow bcx+acy+abz=0\)

Vì \(\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=2\)

\(\Rightarrow\left(\frac{a}{x}+\frac{b}{y}+\frac{c}{z}\right)^2=4\)

\(\Rightarrow\left(\frac{a}{x}\right)^2+\left(\frac{b}{y}\right)^2+\left(\frac{c}{z}\right)^2+2\left(\frac{ab}{xy}+\frac{bc}{yz}+\frac{ca}{zx}\right)=4\)

\(\Rightarrow\left(\frac{a}{x}\right)^2+\left(\frac{b}{y}\right)^2+\left(\frac{c}{z}\right)^2=4\)