Đặt \(\frac{a}{b}=\frac{c}{d}=k\Rightarrow\hept{\begin{cases}a=bk\\c=dk\end{cases}}\)
\(\frac{3a+5b}{3a-5b}=\frac{3bk+5b}{3bk-5b}=\frac{b\left(3k+5\right)}{b\left(3k-5\right)}=\frac{3k+5}{3k-5}\)
\(\frac{3c+5d}{3c-5d}=\frac{3dk+5d}{3dk-5d}=\frac{d\left(3k+5\right)}{d\left(3k-5\right)}=\frac{3k+5}{3k-5}\)
Vậy từ \(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\) chứng minh \(\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
cho \(\frac{a}{b}=\frac{c}{d}\)
Chứng minh:\(\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
Cho tỉ lệ thức : \(\frac{a}{b}=\frac{c}{d}\) . Chứng minh
\(\frac{3a+5b}{3a-5b}\)= \(\frac{3c+5d}{3c-5d}\)
Cho\(\frac{3a+5b}{2a-b}=\frac{3c+5d}{2c-d}CMR\frac{a}{b}=\frac{c}{d}\)
Cho\(\frac{3a+5b}{2a-b}=\frac{3c+5d}{2c-d}CMR\frac{a}{b}=\frac{c}{d}\)
cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\).chứng minh
a)\(\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
b) \(\frac{2a+3b}{2a-3b}\)=\(\frac{2c+3d}{2c-3d}\)
cho tỉ lệ thức \(\frac{a}{b}\)= \(\frac{c}{d}\),cmr ta có tỉ lệ thức sau:
a) \(\frac{3a+5b}{3a-5b}\)= \(\frac{3c+5d}{3c-5d}\)
b) \(\frac{7a^2+5ac}{7a^2-5ac}\)=\(\frac{7b^2+5bd}{7b^2-5bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)Chứng minh \(\frac{3a+7b}{3a-5b}=\frac{3c+7d}{3c-5d}\)
