Đặt a/b=c/d=k => a=bk, c=dk thay vào ta có
VT=a^2+ac/c^2-ac=(bk)^2+bkdk/(dk)^2-bkdk=bk^2(b+d)/dk^2(b-d)=b(b+d)/d(d-b)
VP=b^2+bd/d^2-bd=b(b+d)/d(d-b)=VT (dpcm)
K mk nha
Cho \(\frac{a}{b}=\frac{c}{d}CMR:\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}CMR:\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}CMR:\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)
CMR:\(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
Admin ơi giúp em làm bài nha :
Cho \(\frac{a}{b}=\frac{c}{d}\). CMR :
\(\frac{a^2+c^2}{b^2+d^2}=\frac{ac}{bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\). CMR \(\frac{a^2+ac}{c^2-ac}=\frac{a^2-bd}{c^2+bd}\)
\(Cho\frac{a}{b}=\frac{c}{d}\)
CMR \(\frac{ac}{bd}=\frac{a^2+c^2}{b^2+d^2}\)
Cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\)
CMR \(\frac{ac}{bd}=\frac{a^2+c^2}{b^2+d^2}\)
Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh rằng: \(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
