Các câu hỏi tương tự
Cho \(\frac{a}{2b}=\frac{b}{2c}=\frac{c}{2d}=\frac{d}{2a},\left(a,b,c>0\right)\)
Tính giá trị biểu thức C=\(\frac{2017a-2016b}{c+d}+\frac{2017b-2016c}{a+d}+\frac{2017c-2016d}{a+b}+\frac{2017d-2016a}{b+c}\)
Bài 1 cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh
d) \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
e) \(\frac{2016a-2017b}{2017c+2018d}=\frac{2016c-2017d}{2017a+2018b}\)
cho ti le thuc \(\frac{a}{b}\)=\(\frac{c}{d}\).Chung minh: \(\frac{2015a-2016b}{2016a+2017b}\)=\(\frac{2015c-2016d}{2016c+2017d}\)
1) Cho frac{a}{b}frac{c}{d}CMR:a) left(frac{a+b}{c+d}right)^2frac{a^2+b^2}{c^2+d^2}b) frac{7a^2+5ac}{7a^2+5ac}frac{7b^2+5bd}{7b^2+5bd}Sử Dụng Tính Chất Của Dãy Tỉ Số Bằng Nhau2) Cho frac{a}{2003}frac{b}{2004}frac{c}{2005}CMR:4left(a-bright)left(b-cright)left(c-dright)^23) Cho frac{a}{b}frac{c}{d}CMR: frac{2015a-2016b}{2016c+2017d}frac{2015c-2016d}{2016a+2017b}
Đọc tiếp
1) Cho \(\frac{a}{b}\)\(=\)\(\frac{c}{d}\)
CMR:
a) \(\left(\frac{a+b}{c+d}\right)^2\)\(=\)\(\frac{a^2+b^2}{c^2+d^2}\)
b) \(\frac{7a^2+5ac}{7a^2+5ac}=\frac{7b^2+5bd}{7b^2+5bd}\)
Sử Dụng Tính Chất Của Dãy Tỉ Số Bằng Nhau
2) Cho \(\frac{a}{2003}=\frac{b}{2004}=\frac{c}{2005}\)
CMR:
\(4\left(a-b\right)\left(b-c\right)=\left(c-d\right)^2\)
3) Cho \(\frac{a}{b}=\frac{c}{d}\)
CMR: \(\frac{2015a-2016b}{2016c+2017d}=\frac{2015c-2016d}{2016a+2017b}\)
Cho \(\frac{a}{b}\)= \(\frac{c}{d}\). CMR:
a) \(\frac{2a+7b}{3a-4b}\)= \(\frac{2c+7d}{3c-4d}\)
b) \(\frac{2015a-2016b}{2016c+2017d}\)= \(\frac{2015c-2016d}{2016a+2017b}\)
Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh rằng: \(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh rằng : \(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh rằng \(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)
Chứng minh rằng: \(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{d^2-bd}\)