Các câu hỏi tương tự
So sánh A=\(\frac{2017^{2017}}{1+2017+2017^2+....+2017^{2016}}\)
B=\(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
So sánh A= \(\frac{2017^{2017}}{1+2017+2017^2+...+2017^{2016}}\)
B= \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
SO SÁNH:
A = \(\frac{2017^{2017}}{1+2017+2017^2+...+2017^{2016}}\)
B = \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
so sánh A=2017^37+2016^2017+1/2017^38 và 2017^38+2016^2017+2/2017^39
So sánh
A=
20172017
1+2017+20172+...+20172016
B=
20162017
1+2016+20162+...+20162016
Cho T=2/2^1+3/2^2+....+2016/2^2015+2017/2^2016
So sánh T với 3
SO SÁNH A VÀ B:
A = \(\frac{2017^{2016}}{1+2017+2017^2+...+2017^{2016}}\)
B = \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
so sánh A và B, biết:
A= \(\frac{2017^{2017}}{1+2017+2017^2+...+2017^{2016}}\) B= \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
Bài 1: So sánh:
A = 20162017 + 2 / 20162017 -1
và B = 20162017/ 20162017 - 3