Xét \(\Delta OAC\) có : \(OA=OC\)
\(\Leftrightarrow\Delta OAC\) cân tại O
\(\Leftrightarrow\widehat{OAC}=\widehat{OCA}\)
Ta có :
\(sđ\stackrel\frown{BC}=\widehat{BOC}=2\widehat{CAB}\)
\(\Leftrightarrow\widehat{BAC}=\dfrac{1}{2}sđ\stackrel\frown{BC}\left(đpcm\right)\)