\(a,A=\dfrac{1}{27}x^2y^2.3xyz^2=\dfrac{1}{9}x^3y^3z^2\)
Hệ số: `1/9`
Biến: x3y3z2
b, Bậc: 8
c, Thay x=-2, y=-1, z=-3 vào A ta có:
\(A=\dfrac{1}{9}x^3y^3z^2=\dfrac{1}{9}.\left(-2\right)^3.\left(-1\right)^3.\left(-3\right)^2=\dfrac{1}{9}.\left(-8\right).\left(-1\right).9=8\)