Question

cho da thuc P = (-2/3x^3y^2)(1/2x^2y^5) a) thu gon da thuc P roi xac dinh he so va phan bien cua don thuc ?

b) tinh gia tri cua P tai x = -1 , y =1

Answer 1

khó thể xem trên mạng

Answer 2

(\(\frac{-2}{3}\)x\(^3\)y\(^2\))(\(\frac{1}{2}\)x\(^2\)y\(^5\))

Answer 3

úi rồi

Answer 4

\(P=\left(\frac{-2}{3}x^3y^2\right)\left(\frac{1}{2}x^2y^5\right)\)

\(P=\frac{-2}{3}x^3y^2.\frac{1}{2}x^2y^5\)

\(P=\left(\frac{-2}{3}.\frac{1}{2}\right)x^{3+2}y^{2+5}\)

\(P=\frac{-1}{3}x^5y^7\)

Thay \(x=-1\); \(y=1\)vào P ta có:

\(P=\frac{-1}{3}\left(-1^5\right)1^7\)

\(P=\frac{-1}{3}.\left(-1\right).1\)

\(P=\frac{1}{3}.1=\frac{1}{3}\)

Vậy : \(P=\frac{1}{3}\)Tại \(x=-1\)\(y=1\)

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