C= 1/100-(1/100.99+.....+1/3.2+1/2.1)
Ta lần lượt có :
1/2.1=1-1/2
1/2.3=1/2-1/3
................
nên C= 1/100-(1-1/100)=1/100-99/100 =-49/50
nên 50C= -49
Cho \(c=\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-....-\frac{1}{3.2}-\frac{1}{2.1}\) .
Khi đó 50C =
Cho C =\(\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
Khi đó 50C =
Cho \(C=\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
Khi đó \(50C=\)
Cho .
Khi đó =
Cho .
Khi đó =
Cho \(C=\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\).
Khi đó 5C=______
cho C =\(\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
tính nhanh : \(C=\frac{1}{100}-\frac{1}{100.99}\frac{1}{99.98}-\frac{1}{98.97}-...........-\frac{1}{3.2}-\frac{1}{2.1}\)
Cho\(C=\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-...-\frac{1}{3.2}-\frac{1}{2.1}\). Tính 50.C
