Question

Cho các đa thức: \(P\left(x\right)=3x^4-x^3+4x^2+2x=1;Q\left(x\right)=-2x^4-x^2+x-2\)

 

Answer 1

`a)P(x)+Q(x)=3x^4-x^3+4x^2+2x+1-2x^4-x^2+x-2`

                   `=x^4-x^3+3x^2+3x-1`

`b)Q(x)-H(x)=-2x^4-2`

`=>H(x)=Q(x)-(-2x^4-2)`

`=>H(x)=-2x^4-x^2+x-2+2x^4+2`

`=>H(x)=-x^2+x`

`c)` Cho `H(x)=0`

`=>-x^2+x=0`

`=>-x(x-1)=0`

`@TH1:-x=0=>x=0`

`@TH2:x-1=0=>x=1`

Answer 2

\(a,P\left(x\right)+Q\left(x\right)=x^4-x^3+3x^2+3x-1\)

\(b,H\left(x\right)=Q\left(x\right)+2x^4+2=-2x^4-x^2+x-2+2x^4+2=-x^2+x\)

\(c,H\left(x\right)=-x^2+x=x\left(1-x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Answer 3

a)\(P\left(x\right)+Q\left(x\right)=x^4-x^3+3x^2-1+3x\)

b)\(H\left(x\right)=Q\left(x\right)+2x^4+2\)

\(H\left(x\right)=-2x^4-x^2+x-2+2x^4+2\)

\(H\left(x\right)=-x^2+x\)

c) cho H(x) = 0

\(=>-x^2+x=0\Leftrightarrow x\left(1-x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)