Các câu hỏi tương tự
a)Cho vi du ve 1 don thuc ,1 da thuc nhung khong phai la don thuc ,2 don thuc dong dang voi nhau ,da thuc 1 bien
b)Hay viet 1 don thuc dong dang voi don thuc don thuc xy\(^3\) sao cho tai x=-1 y=2 gia tri cua don thuc do la so nguyen duong nho hon 10
bai 1: Cho cac don thuc A=-4/9x^3y va B= 3/8 x^5y^3. Tim cac cap gia tri (x;y)de A,B cung gia tri am
bai 2: viet don thuc B=64xy^12 duoi dang luy thua cua 1 don thuc voi so mu khac 1
bai 3: cho A=8x^5y^3; B=-3x^6y^3; C=-6x^7y^2. CM: Ax^2+Bx+C>0
dang I. Tim gia tri bieu thucBai 5: Cho x - y 9, tinh gia tri cua bieu thucBfrac{4x-9}{3x+y}-frac{4y+9}{3y+x}(x khac -3y, y khac -3x)Bai 6: Hay viet cac da thuc duoi dang tong cua cac don thuc roi thu gon. tinh gia tri bieu thuc khi x-1, y1a,D4x(x+y)-5y(x-y)-4x^2 b,E(a-1)(x^2+1)-x(y+1)+(x+y^2-a+1)moi nguoi giup minh di hu hu
Đọc tiếp
dang I. Tim gia tri bieu thuc
Bai 5: Cho x - y =9, tinh gia tri cua bieu thuc
B=\(\frac{4x-9}{3x+y}\)-\(\frac{4y+9}{3y+x}\)(x khac -3y, y khac -3x)
Bai 6: Hay viet cac da thuc duoi dang tong cua cac don thuc roi thu gon. tinh gia tri bieu thuc khi x=-1, y=1
a,D=4x(x+y)-5y(x-y)-4x\(^2\) b,E=(a-1)(x\(^2\)+1)-x(y+1)+(x+y\(^2\)-a+1)
moi nguoi giup minh di hu hu
Cho 3 don thuc \(\frac{5}{3}x^2y^5z^3;\frac{-2}{5}x^3yzt^2;\frac{3}{7}x^{15}y^4z^2\)
Trong do cac bien x, y, z, t khac 0
Chung minh rang trong 3 don thuc da cho co it nhat 1 don thuc gia tri am.
1.Tan so cua mot gia tri la gi?Co nhan xet gi ve tong cac tan so?
2.Cho mot so vi du ve don thuc
3.Hay viet mot da thuc va chi ro cac hang tu cua da thuc do
4.Viet hai da thuc roi tinh tong cua chung
5.Tinh
a,(x+y)+(x-y) b,(x+y)-(x-y)
cho bieu thuc:
A=(6-2/3+1/2)-(5+5/3-3/2)-(3-7/3+5/2)
hay tinh gia tri cua A theo hai cach
cach 1:truoc het tinh gia tri tung bieu thuc trong ngoac
cach 2:bo dau ngoac roi nhom cac so hang thich hop
THU GON DON THUC SAU VA CHO BIET PHAN HE SO ,PHAN BIEN CUA DON THUC THU DUOC
-AX(xy^3).1/4.(-by)^3 (voi a,b la hang so)
cac ban oi giup minh voi
NHan cac don thuc sau va tim bac va he so cua don thuc nhan duoc:
(\(\frac{1}{3}\)x\(^3\)y).(-xy)\(^2\)
NHan cac don thuc sau va tim bac va he so cua don thuc nhan duoc:
(\(\frac{1}{3}\)x\(^3\)y).(-xy)\(^2\)