Ta có: D = \(\frac{2n+6+1}{n+3}\)
= \(\frac{2\left(n+3\right)+1}{n+3}\)
= 2 + \(\frac{1}{n+3}\)
Vì 2 nguyên nên để D nguyên thì \(\frac{1}{n+3}\)\(\in\)Z
\(\Rightarrow\)n + 3 \(\in\)Ư(1) (vì n \(\in\)Z)
\(\Rightarrow\orbr{\begin{cases}n+3=1\\n+3=-1\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}n=-2\\n=-4\end{cases}}\)
Vậy.....
cho B=n/n-3(n thuoc Z , n khac 3)
tim tat ca cac gia tri nguyen cua n de B la so nguyen
CHo C= 3n+5.n+7(n thuoc Z, N khac -7)
tim tat ca cac gia tri nguyen cua n de C la so nguyen
cho bieu thuc 2n+1/n+5(n thuoc Z)
a, tim n de Pco gia tri la 1 so nguyen
b,tim gia tri lon nhat,gia tri nho nhat cua P
cho bieu thuc a=2n+2/2n-4 (N thuoc Z)
a) voi gia tri nao cua n de a la phan so
b) tim cac so co gia tri cua n de là so nhuyen
2n+2 phan 2n-4
Cho cac bieu thuc
A=n+6 phan n-5 va B=3n-9 phan n-6
a/ Tim gia tri nguyen cua n de A, B la phan so ?
b/ Tim gia tri nguyen cua n de A, B co gia tri nguyen?
c/ Tim gia tri nguyen cua n de A, B co gia tri nguyen lon nhat?
cho bieu thuc :A=2n+1/n-3+3n-5/n-3-4n-5/n-3.a, tim n de a nhan gia tri nguyen .b,tim n de a la phan so toi gian
1) Cho bieu thuc : A= 2n +1 /n-3 + 3n-5/ n-3 - 4n-5 /n-3
a)Tim so nguyen n de A nhan gia tri nguyen
b) Tim n de A la phan so toi gian
tim tat ca cac so nguyen n de bieu thuc A=2n-3/n-2 dat gia tri lon nhat
1. Cho bieu thuc A=\(\frac{-4}{n-1}\)(voi n\(\in\)Z)
a. So nguyen n phai co dieu Kien gi de A la Phan so
b. Tin cac so nguyen n de A co gia tri nguyen
2. Cho Phan so B= \(\frac{n}{n-4}\)(voi n\(\in\)Z)
a. Tim cac so Nguyen n de B la phan so
b. Tim tat ca cac so nguyen n de B co gia tri nguyen
3. Chung minh rang cac Phan so sau Co gia tri la so tu nhien
a. \(\frac{10^{2016}+2}{3}\)
b.\(\frac{10^{2016}+8}{9}\)
tim n thuoc n de cac phan so sau co gia tri nguyen 2n+3/7
