\(đkxđ\Leftrightarrow x\ge\sqrt{x^2-4x+4}\)\(\Rightarrow x\ge|x-2|\Rightarrow x\ge0\)
\(A=\sqrt{x-\sqrt{x^2-4x+4}}.\)
\(=\sqrt{x-\sqrt{\left(x-2\right)^2}}\)
\(=\sqrt{x-|x-2|}=0\)
Nếu \(x\ge2\Rightarrow A=\sqrt{x-\left(x-2\right)}=\sqrt{x-x+2}=\sqrt{2}\)
Nếu \(0\le x< 2\Rightarrow A=\sqrt{x-\left(2-x\right)}=\sqrt{2x-2}\)