Các câu hỏi tương tự
rut gon \(y=\frac{2x+2}{\sqrt{x}}+\frac{x\sqrt{x}-1}{x-\sqrt{x}}-\frac{x^2+\sqrt{x}}{x\sqrt{x}+x}\)
cmr voi moi gia tri cua x de Y co nghia thi bieu thuc \(\frac{7}{y}\)chi nhan moi gia tri nguyen
a\Rut gon bieu thuc
b/Tim gia tri nho nhat cua 4A
A=\(\frac{5\sqrt{x}+4}{x+\sqrt{x}-2}+\frac{\sqrt{x}-1}{\sqrt{x}+2}-\)\(\frac{\sqrt{x}+2}{\sqrt{x}-1}\)
Cho bieu thuc P = \(\frac{x-\sqrt{x}}{x+\sqrt{x}+1}\) --\(\frac{2x+\sqrt{x}}{\sqrt{x}}\)+\(\frac{2\left(x-1\right)}{\sqrt{x}-1}\)
a) rut gon P
b) tim x de Q=\(\frac{2\sqrt{x}}{P}\)nhan gia tri nguyen
cho A= \(\frac{1-\sqrt{x}}{1+\sqrt{x}}\) ,B=\((\frac{15-\sqrt{x}}{x-25}\)+\(\frac{2}{\sqrt{x+5}}\)) : \(\frac{\sqrt{x}+1}{\sqrt{x}-5}\)
a) tinh gia tri bieu thuc A khi x = 16
b) rut gon B
c) tim x để ( B-A) nguyen
\(M=\left(\frac{\sqrt{x}+2}{x+2\sqrt{x}+1}-\frac{\sqrt{x}-2}{x-1}\right)N=\frac{\sqrt{x}+1}{\sqrt{x}}\) voi x>0 va x khac 1
a) tim gia tri bieu thuc cua N khi x = 25
b) rut gon S = M.N
c) tim m de S<-1
cho bieu thuc \(P=\left(\frac{\sqrt{x}-2}{x-1}-\frac{\sqrt{x+2}}{x-2\sqrt{x}+1}\right)\cdot\frac{\left(1-x\right)^2}{2}\)
a) rut gon P
b) tim gia tri lon nhat cua P
Cho bieu thuc: \(p=\left(\frac{1}{\sqrt{x}-\sqrt{x-1}}-\frac{x-3}{\sqrt{x-1}-\sqrt{2}}\right)\left(\frac{2}{\sqrt{2}-\sqrt{x}}-\frac{\sqrt{x}+\sqrt{2}}{\sqrt{2x}-x}\right)\)
a) Tim DKXD cua bieu thuc p
b) Rut gon bieu thuc p
Cho bieu thuc:
P=\(\frac{1}{\sqrt{x}+2}-\frac{5}{x-\sqrt{x}-6}-\frac{\sqrt{x}-2}{3-\sqrt{x}}\)
a. Rut gon bieu thuc P
b.Tim GTLN cua P sau khi rut gon
rut gon bieu thuc A=\(\left(\frac{\sqrt{x}}{x-4}+\frac{2}{2-\sqrt{x}}+\frac{1}{\sqrt{x}+2}\right):\left(\sqrt{x}-2+\frac{10-x}{\sqrt{x}+2}\right)\) tìm giá trị của x để A>0