a, A=(-a+ b - c) - (-a - b - c)
A= -a + b - c + a + b + c
A= (-a + a) + (-c + c) + (b + b)
A= 0 + 0 + 2b
A= 2b
học tốt
Ta có: \(A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(\Leftrightarrow A=-a-b+c+a+b+c\)
\(\Leftrightarrow A=2c\)
hok tốt!!
A=(-a-b+c)-(-a-b-c)
A=-a+b+c+a+b+c
A=(-a+a)+(b+c+b+c)
A=0+2.(b+c)
A=2.(b+c)
ko chắc
A=(-a-b+c)-(-a-b-c)
A=-a-b+c+a+b+c
A=2c
# chúc học tốt #
A=(-a+ b - c) - (-a - b - c)
A= -a + b - c + a + b + c
A= (-a + a) + (-c + c) + (b + b)
A= 0 + 0 + 2b
A= 2b
Cảm ơn ba bạn nhé
A=(-a-b+c)-(-a-b-c)
A= -a-b+c+a+b+c
A= 2c
\(A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(=-a-b+c+a+b+c\)
\(=2c\)
A = (- a - b + c) - (- a - b- c)
A = - a - b + c + a + b+ c
A = (- a + a) - (b - b) + (c + c)
A = 0 - 0 + 2c
A = 2c
\(A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(A=-a-b+c+a+b+c\)
\(A=\left(-a+a\right)+\left(-b+b\right)\left(c+c\right)\)
\(A=0+0+2c\)
\(A=2c\)
Vậy \(A=2c\)
